Page 1034

Alexandr Korol
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Page 1034

Post by Alexandr Korol »

In the two diagrams above, I show that instead of one of the two tetrahedrons forming in the center of my cube, I now show where another triangle — that is, a tetrahedron — could be located if my cube is divided into 8 smaller cubes. So, if we divide my cube into 8 cells (8 smaller cubes), then in one of those 8 cubes, if represented as a tetrahedron pointing up or down, it would be positioned like this, as I show above.